Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
Em | 590 | 58 | 1 | 58.0000 |
Para | 593 | 29 | 1 | 29.0000 |
Mas | 405 | 27 | 1 | 27.0000 |
E | 427 | 24 | 1 | 24.0000 |
Na | 442 | 40 | 2 | 20.0000 |
Com | 390 | 18 | 1 | 18.0000 |
mas | 1254 | 52 | 3 | 17.3333 |
Não | 431 | 33 | 2 | 16.5000 |
No | 624 | 47 | 3 | 15.6667 |
seu | 1286 | 124 | 9 | 13.7778 |
sua | 1586 | 137 | 10 | 13.7000 |
O | 3856 | 276 | 21 | 13.1429 |
Ao | 153 | 13 | 1 | 13.0000 |
cento | 263 | 13 | 1 | 13.0000 |
As | 601 | 45 | 4 | 11.2500 |
A | 3106 | 258 | 23 | 11.2174 |
Os | 958 | 85 | 8 | 10.6250 |
De | 335 | 20 | 2 | 10.0000 |
Neste | 116 | 10 | 1 | 10.0000 |
neste | 218 | 19 | 2 | 9.5000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
cerca | 332 | 1 | 15 | 0.0667 |
médico | 55 | 1 | 8 | 0.1250 |
jovem | 102 | 1 | 8 | 0.1250 |
Cabo | 76 | 1 | 7 | 0.1429 |
postos | 73 | 1 | 7 | 0.1429 |
algum | 85 | 1 | 7 | 0.1429 |
jogador | 107 | 1 | 7 | 0.1429 |
continuar | 115 | 1 | 7 | 0.1429 |
disso | 115 | 1 | 6 | 0.1667 |
informações | 116 | 1 | 6 | 0.1667 |
contribuir | 52 | 1 | 6 | 0.1667 |
velocidade | 55 | 1 | 6 | 0.1667 |
tipo | 153 | 2 | 12 | 0.1667 |
cor | 62 | 1 | 6 | 0.1667 |
milhões | 594 | 6 | 36 | 0.1667 |
programas | 68 | 1 | 6 | 0.1667 |
tecnologia | 63 | 1 | 6 | 0.1667 |
ponto | 143 | 2 | 11 | 0.1818 |
resultados | 295 | 5 | 27 | 0.1852 |
signo | 27 | 1 | 5 | 0.2000 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II